College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 700: 40


(a) $emf = 3.0~V$ (b) $I = 0.94~A$

Work Step by Step

(a) We can find the equivalent $emf$: $emf = 3.0~V+4.5~V-1.5~V+2.0~V-5.0~V$ $emf = 3.0~V$ (b) We can find the current: $emf = I~R$ $I = \frac{emf}{R}$ $I = \frac{3.0~V}{3.2~\Omega}$ $I = 0.94~A$
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