Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - For Thought and Discussion - Page 146: 4


The answer is below.

Work Step by Step

Recall, $F_{g} = mg$ and $F=ma$. Solving for acceleration, we obtain: $$a = \frac{F}{m} = \frac{mg}{m} =g$$ Thus, all objects fall with constant acceleration, g, regardless of their mass.
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