Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 342: 45

Answer

$T_2=713.2K$

Work Step by Step

We find: $(\frac{V_2}{V_1})^{\gamma-1}=\frac{T_1}{T_2}$ $(.118)^{.4}=\frac{303}{T_2}$ $T_2=713.2K$
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