Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Section 14.5 - Interference - Example - Page 261: 14.5

Answer

16 meters

Work Step by Step

We first use the Pythagorean theorem: $AP = \sqrt{75^2 + 43 ^2 } = \approx 86.5\ m$ $BP = \sqrt{75^2 + 23 ^2 } = \approx 78.4\ m$ Thus, using these values, we can find the wavelength: $\lambda = 2( AP-BP) = 2(86.5-78.4) \approx 16 \ m$
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