Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Section 13.6 - Damped Harmonic Motion - Example - Page 242: 13.6



Work Step by Step

We first find the time: $t = \frac{2m}{b}ln2= \frac{2\times 1200}{230}ln2= 7.23 s$ We now find the period: $T = 2\pi \sqrt{\frac{m}{k}}= 2\pi \sqrt{\frac{1200}{58 \times10^3 }}= .904s$ Thus: $=\frac{7.23s}{.904s}\approx \fbox{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.