Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Section 13.2 - Simple Harmonic Motion - Example - Page 234: 13.2

Answer

$3.18 \times 10^5$ N/m

Work Step by Step

We simplify the equation for period to find k to obtain: $k = \frac{4 \pi ^2 m}{T^2} = \frac{4 \pi ^2 (3.73 \times 10^5)}{6.8^2} =$ $3.18 \times 10^5$ N/m
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