Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 17 - Radioactivity and Nuclear Chemistry - Exercises - Problems - Page 638: 69

Answer

3100 atoms

Work Step by Step

Number of half-lives= $\frac{t}{t_{1/2}}=\frac{10\,d}{2.0\,d}=5.0$ As the sample undergoes 5 half-lives, the initial number of atoms decreases by half 5 times. Number of atoms left=$100,000\times(\frac{1}{2})^{5}=\frac{120}{16}=3.1\times10^{3}\,atoms$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.