Answer
a) $KOH$
b) $KNO_{2}$
c) $K_{2}SO_{4}$
d) $KHSO_{3}$
e) $K_{3}PO_{4}$
f) $KCN$
Work Step by Step
First find the valency of each element. Charge on the ion is the valency of the element. So, valency of potassium is 1. Now, say the charge of anion X is '-n' then the valency of the anion is 'n'. So, the formula of the compound will be $K_{n}X$.
