Answer
$Barometric Pressure, P = 760.67 mm Hg$
Work Step by Step
Using the formula $P=ghd$ where, $P$ is the Barometric (atmospheric) pressure, $g$ is the value of acceleration due to gravity and $d$ is the density of the fluid.
Step 1: Convert the density of diethylene glycol to $kg m^{-3}$ so that the answer obtained when the values are substituted in the formula given above the answer obtained will be in SI base units.
$\frac{1.118 g}{cm^{3}}\times\frac{{(10^{2})}^{3}cm^{3}}{(1^{3})m^{3}}=1118kgm^{-3} $
Step 2: Substitute the given values into the formula given above i.e. $P=ghd$.
$P=?$
$g=9.80655ms^{-2}$
$h=9.25m$
$d=1118kgm^{-3}$
therefore, $P= 9.80655ms^{-2}\times9.25m\times1118kgm^{-3} = 101414.4368 kgm^{-1}s^{-2}$
which is equivalent to $101414.4368 Pa$
Step 3: Convert the Barometric Pressure value obtained in Pascals to mmHg
$1mmHg = 133.322 Pa$
$x \times mmHg = \frac{101414.4368Pa}{133.322Pa} \approx 760.67 mmHg$
