General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 25 - Nuclear Chemistry - Exercises - Self-Assessment Exercises - Page 1146: 90

Answer

(c) 0.363

Work Step by Step

Decay constant=$\frac{\ln 2}{t_{1/2}}=\frac{0.693}{1.91\,y}=0.363\,y^{-1}$ The numerical value of the decay constant is 0.363
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