Answer
The point representing $^{44} \mathrm{Ca}$, in Fig. 27-7, falls in the belt of stability. $^{44} \mathrm{Ca}$ is a stable nuclide. $^{57} \mathrm{Cu}$ falls below the $N=Z$ line and in the region of $\beta^{+}$ emission, while $^{100} \mathrm{Zr}$ falls above the belt of stability and decays by $\beta^{-}$ emission. $^{235} \mathrm{U}$ falls above and beyond the belt of stability and decays by $\alpha$ -particle emission.
Work Step by Step
See answer above.
