General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 225: 5.157


Please see the work below.

Work Step by Step

We know that $V=\frac{nRT}{P}$ We plug in the known value to obtain: $V=\frac{0.41502\times 0.08206\times 500}{15.00}=1.1352L$ We also know that $d=\frac{mass}{volume}$ $d=\frac{10.0g}{1.1352L}=8.808\frac{g}{L}$
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