General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 220: 5.68

Answer

$71.2amu$

Work Step by Step

From ideal gas law $n=\frac{PV}{RT}$ We plug in the known values to obtain: $n=\frac{\frac{755}{760}\times 0.273}{0.08206\times 373}=0.007692mol$ Now we can find the molar mass as $Molar \space mass =\frac{0.548g}{0.007692mol}=71.2\frac{g}{mol}$ Hence the molecular weight is $71.2amu$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.