Answer
$106.2\frac{J}{K}$
Work Step by Step
We know that
$\Delta H=120 mol\times \frac{29.6Kj}{1 mol}=3.552\times 10^4J$
Now $\Delta S=\frac{\Delta H}{T}$
We plug in the known values to obtain:
$\Delta S=\frac{3.552\times 10^{4}}{61.2+273}=106.2\frac{J}{K}$
