General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 17 - Solubility and Complex-Ion Equilibria - Questions and Problems - Page 735: 17.24

Answer

Please see the work below.

Work Step by Step

We know that when a precipitate fails to form by adding HCl to the solution,then this shows that no silver ion is present. Similarly, when a precipitate fails to from by adding $H_2S$ shows that no copper(II) ion is present.
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