Answer
Please see the work below.
Work Step by Step
We know that
$[Ag^+]=\frac{K_{sp}}{Cl^-}$
We plug in the known values to obtain:
$[Ag^+]=\frac{1.8\times 10^{-10}}{0.10M}$
$[Ag^+]=1.80\times 10^{-9}M$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 17 - Solubility and Complex-Ion Equilibria - Questions and Problems - Page 733: 17.3
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