Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 3 - Equations, the Mole, and Chemical Formulas - Questions and Exercises - Exercises: 3.81

Answer

Mass % of Na = 32.37% Mass % of S = 22.575% Mass % of O = 45.055%

Work Step by Step

Mass percentage of an element = (mass of that element in the compound × 100)/(molar mass of the compound) Molar mass of sodium sulfate ($Na_{2}SO_{4}$)= $(2\times22.99g)+(1\times32.065g)+(4\times15.999g)$ = 142.04g Mass % of Na = $\frac{(2\times22.99g)\times100}{142.04g}$ = 32.37% Mass % of S = $\frac{32.065g\times100}{142.04g}$ = 22.575% Mass % of O = $\frac{(4\times15.999g)\times100}{142.04g}$ =45.055%
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