Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Problem Solving Practice 14.6 - Page 622: b

Answer

$HCOOH(aq) + H_2O(l) \lt -- \gt H_3O^+(aq) + HCOO^-(aq)$ $Ka = \frac{[H_3O^+][HCOO^-]}{[HCOOH]}$

Work Step by Step

The ionization equation should describe the transfer of a proton from the acid to a water molecule, therefore, the acid and the water are the reactants, and the protonated water and the conjugate base are the products. The ionization constant expression is based on: $K_a = \frac{[Products]}{[Reactants]}$ * The water doesn't appear, because it is the solvent, and its concentration doesn't matter.
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