Answer
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Work Step by Step
1. Tetrahedral arrangement of electron pairs:
- The central atom in a tetrahedral arrangement of electron pairs requires sp3 hybridization.
- In a tetrahedral arrangement, the central atom has four electron pairs, and the hybridization is sp3 to accommodate these four electron pairs.
2. Trigonal planar arrangement of electron pairs:
- The central atom in a trigonal planar arrangement of electron pairs requires sp2 hybridization.
- In a trigonal planar arrangement, the central atom has three electron pairs, and the hybridization is sp2 to accommodate these three electron pairs.
3. Linear arrangement of electron pairs:
- The central atom in a linear arrangement of electron pairs requires sp hybridization.
- In a linear arrangement, the central atom has two electron pairs, and the hybridization is sp to accommodate these two electron pairs.
4. Tetrahedral geometry:
- When a central atom exhibits tetrahedral geometry, there are 0 unhybridized p atomic orbitals present.
- In a tetrahedral arrangement, the four electron pairs are distributed in the sp3 hybrid orbitals, and there are no unhybridized p orbitals.
5. Trigonal planar geometry:
- When a central atom exhibits trigonal planar geometry, there is 1 unhybridized p atomic orbital present.
- In a trigonal planar arrangement, the three electron pairs are distributed in the sp2 hybrid orbitals, and there is one unhybridized p orbital.
6. Linear geometry:
- When a central atom exhibits linear geometry, there are 2 unhybridized p atomic orbitals present.
- In a linear arrangement, the two electron pairs are distributed in the sp hybrid orbitals, and there are two unhybridized p orbitals.
7. Bonding in H2S, CH4, H2CO, and HCN:
- H2S (Hydrogen Sulfide):
- The central sulfur atom exhibits sp3 hybridization, with two bonding pairs and two lone pairs of electrons.
- The bonding is described using the localized electron model, where the two hydrogen atoms form covalent bonds with the sulfur atom.
- CH4 (Methane):
- The central carbon atom exhibits sp3 hybridization, with four bonding pairs of electrons.
- The bonding is described using the localized electron model, where the four hydrogen atoms form covalent bonds with the carbon atom.
- H2CO (Formaldehyde):
- The central carbon atom exhibits sp2 hybridization, with one double bond to the oxygen atom and two single bonds to the hydrogen atoms.
- The bonding is described using the localized electron model, where the carbon atom forms a double bond with the oxygen atom and two single bonds with the hydrogen atoms.
- HCN (Hydrogen Cyanide):
- The central carbon atom exhibits sp hybridization, with a triple bond to the nitrogen atom and a single bond to the hydrogen atom.
- The bonding is described using the localized electron model, where the carbon atom forms a triple bond with the nitrogen atom and a single bond with the hydrogen atom.