Answer
See the explanation
Work Step by Step
a. The wavelength of the radiation can be calculated using the formula \( \lambda = \frac{c}{\nu} \), where \( \lambda \) is the wavelength, \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)), and \( \nu \) is the frequency of the radiation. Plugging in the given frequency, we get \( \lambda = \frac{3.00 \times 10^8 \, \text{m/s}}{6.0 \times 10^{13} \, \text{s}^{-1}} = 5.00 \times 10^{-6} \, \text{m} \).
b. The wavelength falls in the infrared region of the spectrum.
c. The energy of the radiation per photon can be calculated using the formula \( E = h\nu \), where \( E \) is the energy, \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J s} \)), and \( \nu \) is the frequency of the radiation. Plugging in the given frequency, we get \( E = 6.626 \times 10^{-34} \, \text{J s} \times 6.0 \times 10^{13} \, \text{s}^{-1} = 3.98 \times 10^{-20} \, \text{J} \).
d. The radiation with a frequency of \( 5.4 \times 10^{13} \, \text{s}^{-1} \) is less energetic because it has a lower frequency and therefore lower energy per photon.
