Answer
See the answer below.
Work Step by Step
Energy required:
$11\ g\times 4.0\ J/g.K\times 3.0\ K=132\ J$
Energy per photon:
$E=h\times c/\lambda$
$E=6.626\times10^{-34}\ J.s\times2.998 \times10^8\ m/s\div 0.12\ m=1.66\times10^{-24}\ J$
Number of photons:
$132\ J\div1.66\times10^{-24}\ J/photon=8.0\times10^{25}\ photons\approx 132\ mol$
