Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - 4-8 Spectrophotometry - Case Study - Question - Page 173: 1


$40.05\ mg$

Work Step by Step

Number of moles of $Na_2S_2O_3$ consumed: $0.0425\ M\times 25.3\ mL=1.08\ mmol$ From stoichiometry: $1.08\ mmol\ S_2O_3^{2-}\times\dfrac{1\ mmol\ I_2}{2\ mmol\ S_2O_3^{2-}}\times\dfrac{2\ mmol\ I^-}{1\ mmol\ I_2}\times\dfrac{1\ mmol\ HClO}{2\ mmol\ I^-}= 0.538\ mmol\ HClO$ Which is the number of moles of sodium hypochlorite in the sample, so the mass is: $0.538\ mmol\times 74.44\ mg/mmol=40.05\ mg$
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