## Chemistry and Chemical Reactivity (9th Edition)

$CdCl_2+2\ NaOH\rightarrow Cd(OH)_2+2\ NaCl$ $Cd^{2+}(aq)+2\ OH^-(aq)\rightarrow Cd(OH)_2(s)$
Balancing the chlorines: $CdCl_2+NaOH\rightarrow Cd(OH)_2+2\ NaCl$ For the sodiums: $CdCl_2+2\ NaOH\rightarrow Cd(OH)_2+2\ NaCl$ Which is fully balanced. The only insoluble component is cadmium (||) hydroxide so the net ionic equation is: $Cd^{2+}(aq)+2\ OH^-(aq)\rightarrow Cd(OH)_2(s)$