Answer
$CdCl_2+2\ NaOH\rightarrow Cd(OH)_2+2\ NaCl$
$Cd^{2+}(aq)+2\ OH^-(aq)\rightarrow Cd(OH)_2(s)$
Work Step by Step
Balancing the chlorines:
$CdCl_2+NaOH\rightarrow Cd(OH)_2+2\ NaCl$
For the sodiums:
$CdCl_2+2\ NaOH\rightarrow Cd(OH)_2+2\ NaCl$
Which is fully balanced.
The only insoluble component is cadmium (||) hydroxide so the net ionic equation is:
$Cd^{2+}(aq)+2\ OH^-(aq)\rightarrow Cd(OH)_2(s)$
