Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - 2-10 Chemical Analysis: Determining Compound Formulas - Review & Check for Section 2-10 - Page 93: 4



Work Step by Step

Molar masses: $MgSO_4: 120.361\ g/mol,\ H_2O: 18.015\ g/mol$ Initially the number of moles: $2.465\ g = n \times (120.361+7\times18.015)g/mol$ $n=0.01\ mols$ After heating $1.744\ g = 0.01\ mol \times( 120.361 + k\times18.015)g/mol$ $k=3.0$ So the formula of the dehydrated salt is: $MgSO_4 (H_2O)_3$
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