## Chemistry and Chemical Reactivity (9th Edition)

$V=270.3\ L$
From item 1, there are $4.092\times10^{-3}\ mols$ of $CO_2$ in the headspace, therefore: $3.7\times10^{-4}\ atm\times V=4.092\times10^{-3}\ mol\times0.082\ atm.L/mol.K\times (273+25)K$ $V=270.3\ L$