## Chemistry 9th Edition

The complete ionic equation is the following: $$Pb(NO_3)_{2(s}+2KI_{(s)} \Rightarrow PbI_{2(s)}+2K^{+}_{(aq)}+2NO_{3(aq)}^{-}$$ Because $KNO_3$ is soluble and dissociates into ions, the solution above the yellow precipitate is conductive.