Answer
$$NH_4Cl, N_2O, NaNO_2, NO_2, HNO_3$$
Work Step by Step
The oxidation state of the nitrogen atom is as follows:
$HNO_3$: +5
$NH_4Cl$: -3
$N_2O$: +1
$NO_2$: +4
$NaNO_2$: +3
Ordering these from lowest to highest oxidations states, we find:
$$NH_4Cl, N_2O, NaNO_2, NO_2, HNO_3$$