## Chemistry 9th Edition

$$NH_4Cl, N_2O, NaNO_2, NO_2, HNO_3$$
The oxidation state of the nitrogen atom is as follows: $HNO_3$: +5 $NH_4Cl$: -3 $N_2O$: +1 $NO_2$: +4 $NaNO_2$: +3 Ordering these from lowest to highest oxidations states, we find: $$NH_4Cl, N_2O, NaNO_2, NO_2, HNO_3$$