Answer
$Mg (s) + 2HCl (aq) → MgCl_2(aq) + H_2(g)$
Work Step by Step
When solid Magnesium is dropped into aqueous Hydrogen Chloride ($HCl$), the magnesium would disappear/dissolve into the chlorine, creating aqueous $MgCl_2$. Alongside this, hydrogen gas is released, with the formula $H_2$. This final equation can be balanced by changing the coefficient of $HCl$ to 2, this allows for both sides of the equation to have equal amounts of atoms.
$Mg (s) + 2HCl (aq) → MgCl_2(aq) + H_2(g)$