Answer
$\nu=1.06\times 10^{15}Hz$
Work Step by Step
$E_m=h\times \nu\times N_A\implies \nu=\frac{E_m}{h\times N_A}=\frac{419000\frac{J}{mol}}{6.62\times10^{-34}Js\times 6\times 10^{23} \frac{1}{mol}}=1.06\times 10^{15}Hz$
Chemistry 10th Edition
by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.
Published by
Brooks/Cole Publishing Co.
ISBN 10:
1133610668
ISBN 13:
978-1-13361-066-3
Chapter 5 - Chemical Periodicity - Exercises - Building Your Knowledge - Page 206: 90
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