Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 14 - Solutions - Exercises - Boiling Point Elevation and Freezing Point Depression: Solutions of Nonelectrolytes - Page 545: 46

Answer

$101.52^{\circ}C$

Work Step by Step

$\Delta T_{b}=K_{b}\times m= 0.512^{\circ}C/m\times2.97\,m$ $=1.52^{\circ}C$ $T_{b}(solution)=T_{b}(solvent)+\Delta T_{b}$ $=100^{\circ}C+1.52^{\circ}C=101.52^{\circ}C$
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