Answer
$c(NaOH) = 0.0963 M$
Work Step by Step
Considering stoichiometric coefficients, we can conclude that the amount of sodium - hydroxide required is equal to the amount of hydrochloric acid.
$n(NaOH) = n(HCl) = c(HCl)\times V(HCl) = 0.101\frac{mol}{dm^3}\times 0.0176 dm^3 = 0.0017776mol$
Hence, the molarity of $NaOH$ solution is equal to:
$c(NaOH) = \frac{n(NaOH)}{V(NaOH)} = \frac{0.0017776mol}{0.01845dm^3} = 0.0963 M$
