Answer
$n(acid) : n(base) = $
1) $1:1$
2) $1:1$
3) $1:1$
4) $1:2$
5) $1:1$
Work Step by Step
1) $NaOH + H_{2}SO_{3} \rightarrow NaHSO_{3} + H_{2}O$
$n(acid) : n(base) = 1:1$
2)$NaOH + CO_{2} \rightarrow NaHCO_{3}$
$n(acid) : n(base) = 1:1$
3)$KOH + H_{3}PO_{4} \rightarrow KH_{2}PO_{4} + H_{2}O$
$n(acid) : n(base) = 1:1$
4)$2NaOH + H_{3}PO_{4} \rightarrow Na_{2}HPO_{4} + 2H_{2}O$
$n(acid) : n(base) = 1:2$
5)$NaOH + H_{2}S \rightarrow NaHS + H_{2}O$
$n(acid) : n(base) = 1:1$
