Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapters 1-8 - Cumulative Test - Page 477: 12

Answer

See below.

Work Step by Step

Using the learned identities: $\sec^2x\csc^2x=\frac{1}{\cos^2x\sin^2x}=\frac{\cos^2x+\sin^2x}{\cos^2x\sin^2x}=\frac{1}{\cos^2x}+\frac{1}{\sin^2x}=\sec^2x+\csc^2x$ Hence we proved what we had to.
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