Answer
$y=2$ with $x=5$ or $x=-2$
Work Step by Step
By equating the real and imaginary parts we get the following equations: $16=8y\\y=2$, $x^2-3x=10\\x^2-3x-10=0\\(x-5)(x+2)=0$
Thus $y=2$ with $x=5$ or $x=-2$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 8 - Test - Page 474: 2
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