Answer
$b$
Work Step by Step
$\sin{A} \cos{B} =\dfrac{1}{2}[\sin{(A+B)} + \sin{(A-B)}]$
$6 \sin{4x} \sin{3x} = 3[\cos{x} - \cos{7x}]$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.5 - Additional Identities - 5.5 Problem Set - Page 312: 56
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