Answer
$\textbf{V}_{x}=343$
$\textbf{V}_{y}=251$
Work Step by Step
$\textbf{V}_{x}=|\textbf{V}|\cos\theta=425\times\cos(36^{\circ}10')=425\times\cos(36\frac{1}{6})^{\circ}$
$=425\times\cos(\frac{217}{6})^{\circ}=343$
$\textbf{V}_{y}=|\textbf{V}|\sin\theta=425\times\cos(36^{\circ}10')=425\times\sin(\frac{217}{6})^{\circ}=251$
