Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.1 - Definition II: Right Triangle Trigonometry - 2.1 Problem Set: 26


$50^{\circ}$ $ \cos 40^{\circ} = \sin 50^{\circ}$

Work Step by Step

$ \cos 40^{\circ} = \sin 50^{\circ}$ Reason- cosine and sine are cofunctions and $ 40^{\circ} + 50^{\circ} = 90^{\circ}$
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