Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.1 - Definition II: Right Triangle Trigonometry - 2.1 Problem Set - Page 62: 26

Answer

$50^{\circ}$ $ \cos 40^{\circ} = \sin 50^{\circ}$

Work Step by Step

$ \cos 40^{\circ} = \sin 50^{\circ}$ Reason- cosine and sine are cofunctions and $ 40^{\circ} + 50^{\circ} = 90^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.