Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 1 - Section 1.1 - Angles, Degrees, and Special Triangles - 1.1 Problem Set: 19


α = $ 30^{\circ}$

Work Step by Step

In given figure 21- $\angle$ CDB is right angle and ADB is a straight line, therefore $\angle$ CDA is also a right angle and hence triangle CDA is a right triangle. In right triangle CDA, C and A are acute angles, therefore- C + A = $90^{\circ}$ α + 2 α = $90^{\circ}$ ( Substituting values of C and A ) 3 α = $90^{\circ}$ α = $\frac{90^{\circ}}{3}$ = $30^{\circ}$
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