Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.1 Oblique Triangles and the Law of Sines - 7.1 Exercises: 5

Answer

$\angle C = 95^{\circ}$ $B \approx 19$ m $A \approx 11$ m

Work Step by Step

1. Find $\angle C$ $\angle C = 180 - (\angle B + \angle A)$ $= 180 - (48+37)$ $= 180 - 85$ $= 95^{\circ}$ 2. Find $B$ $\frac{B}{sin(48)} = \frac{18}{sin(95)}$ $B = \frac{18sin(48)}{sin(95)}$ by GDC / calculator $B = 18.917...$m $B \approx 19$ m 3. Find $A$ $\frac{A}{sin(37)} = \frac{18}{sin(95)}$ $A = \frac{18sin(37)}{sin(95)}$ by GDC / calculator $A = 10.874...$ m $A \approx 11$ m
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