Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.2 Trigonometric Equations I - 6.2 Exercises - Page 266: 4

Answer

1) Given equation is quadratic. 2) Only one trigonometric function i.e. $\cos x$ is present. 3) Equation may be rearranged to make R.H.S. equal to zero. 3) Now L.H.S. can be factorized easily. 4) Now each factor may be set equal to zero for final solution.

Work Step by Step

Given equation is- $2 \cos^{2} x $ - $ \cos x$ = $1$ Steps to be taken- 1) Given equation is quadratic. 2) Only one trigonometric function i.e. $\cos x$ is present. 3) Equation may be rearranged to make R.H.S. equal to zero. 3) Now L.H.S. can be factorized easily. 4) Now each factor may be set equal to zero for final solution.
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