Answer
$\sin\theta=\frac{y}{r}=\frac{-5}{\sqrt {26}}=-\frac{5\sqrt {26}}{26}$
$\cos\theta=\frac{x}{r}=\frac{1}{\sqrt {26}}=\frac{\sqrt {26}}{26}$
$\csc\theta=\frac{r}{y}=\frac{\sqrt {26}}{-5}=-\frac{\sqrt {26}}{5}$
$\sec\theta=\frac{r}{x}=\frac{\sqrt {26}}{1}=\sqrt {26}$
$\tan\theta=\frac{y}{x}=\frac{-5}{1}=-5$
$\cot\theta=\frac{x}{y}=\frac{1}{-5}=-\frac{1}{5}$
Work Step by Step
x=1; y=-5
$r=\sqrt {x^{2}+y^{2}}=\sqrt {(1)^{2}+(-5)^{2}}=\sqrt {26}$
