Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Trigonometric Identities - Section 5.1 Fundamental Identities - 5.1 Exercises - Page 200: 22



Work Step by Step

$$\csc\theta=-\frac{8}{5}$$ We have the following identity $$\csc\theta=\frac{1}{\sin\theta}\hspace{1cm}\text{(Reciprocal Identities)}$$ so, $$\sin\theta=\frac{1}{\csc\theta}$$ $$\sin\theta=\frac{1}{-\frac{8}{5}}=-\frac{5}{8}$$
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