Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Quiz (Sections 4.1-4.2) - Page 164: 6

Answer

$y = 2+sin~(2x-\pi)$ We can see the graph below. The period is $\pi$ The amplitude is $1$

Work Step by Step

$y = 2+sin~(2x-\pi)$ When $x = 0$, then $y = 2+sin~(-\pi) = 2$ When $x = \frac{\pi}{4}$, then $y = 2+sin~(-\frac{\pi}{2}) = 1$ When $x = \frac{\pi}{2}$, then $y = 2+sin~(0)= 2$ When $x = \frac{3\pi}{4}$, then $y = 2+sin~(\frac{\pi}{2}) = 3$ When $x = \pi$, then $y = 2+sin~(\pi) = 2$ We can see the graph below. The period is $\pi$ The amplitude is $1$
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