Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.3 Finding Trigonometric Function Values Using a Calculator - 2.3 Exercises - Page 70: 86

Answer

$D=194ft$

Work Step by Step

Using the same values as in Exercise 85 except for the new value for $\theta=-2^{\circ}$. Substituting in the formula, $D=\frac{1.05(V_{1}^{2}-V_{2}^{2})}{64.4(K_{1}+K_{2}+\sin\theta)}$ $D=\frac{1.05(80.67^{2}-44^{2})}{64.4(0.4+0.02+\sin(-2^{\circ}))}$ $D=193.55ft$ $D\approx194ft$
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