Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 29: 93

Answer

0

Work Step by Step

1.First lets find the values of the trig functions of the given angles. $\sec180^{\circ}=-1$ $\sin360^{\circ}=0$ $\cos180^{\circ}=-1$ 2. Then just plug those values into expression: $(-1)^{2} -3(0)^{2}+(-1) =0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.