Answer
100 is a number large enough so that the sampling distribution of $x ̅$ is approximately normal. It also has $μ_ {x ̅}=-0.05~dollars$ and $σ_{x ̅}=0.576~dollars$
Work Step by Step
$μ_ {x ̅}=μ_X=-0.05$
$σ_{x ̅}=\frac{σ_X}{\sqrt {n}}=\frac{5.76}{\sqrt {100}}=0.576$
