Answer
$μ_ {x̅}= 2.35$
$σ_{x̅} = 0.305$
Work Step by Step
According to the Central Limit Theorem, if the sample size is $n \geq 30$, we can assume a normal distribution. Here, n = 40. Hence, the distribution is approximately normal.
$μ_ {x̅}= μ = 2.35$
$σ_{x̅} = \frac{σ}{n} = \frac{1.93 }{\sqrt 40} = 0.305$
