Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 8 - Review - Review Exercises - Page 422: 10b

Answer

$P(p̂ \geq 0.31) = 0.0681$. Hence it iwll not be unusual, as the probability > 0.05.

Work Step by Step

To calculate $P(p̂ \geq 0.31)$, we need to find the z-score: $z = \frac{p̂ - μ_{p̂}}{σ_{p̂}}$ $= \frac{.31-.28}{0.02}$ = 1.49 $P(z \geq 1.49) = 0.0681$, hence: $P(p̂ \geq 0.31) = 0.0681$ (not unusual)
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