Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 3 - Section 3.3 - Assess Your Understanding - Applying the Concepts - Page 162: 4

Answer

$μ=29.9$ $σ=20.3$

Work Step by Step

$x_1=$ First Class Midpoint = 9 $x_2=$ Second Class Midpoint = 21.5 $x_3=$ Third Class Midpoint = 30 $x_4=$ Fourth Class Midpoint = 40 $x_5=$ Fifth Class Midpoint = 50 $x_6=$ Sixth Class Midpoint = 57.5 $x_7=$ Seventh Class Midpoint = 62.5 $x_8=$ Eigth Class Midpoint = 70 $μ=\frac{Σx_if_i}{Σf_i}=\frac{9\times15451+21.5\times6071+30\times6123+40\times4756+50\times4421+57.5\times1792+62.5\times1520+70\times3433}{43567}=29.9$ $σ=\sqrt {\frac{Σ(x_i-μ)^2f_i}{Σf_i}}=\sqrt {\frac{(9-29.9)^2\times15451+(21.5-29.9)^2\times6071+(30-29.9)^2\times6123+(40-29.9)^2\times4756+(50-29.9)^2\times4421+(57.5-29.9)^2\times1792+(62.5-29.9)^2\times1520+(70-29.9)^2\times3433}{43567}}=20.3$
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