Answer
At a minimum, 75% of the bulbs will have a lifetime between 494 and 706 hours.
Work Step by Step
Put x̅ = 2
x̅ - 2s = 600 - 2 (53) = 494
x̅ + 2s = 600 + 2 (53) = 706
Using Chebyshev's inequality:
$(1 - 1/2^{2})100\% = 75\%$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 3 - Review - Review Exercises - Page 184: 5f
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